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MHT CET · Physics · Rotational Motion

A body of mass' \(\mathrm{m}\) ' and radius of gyration ' \(\mathrm{K}\) ' has an angular momentum ' \(L\) '. Then its angular velocity is

  1. A \(\frac{\mathrm{L}}{\mathrm{mK}^2}\)
  2. B \(\frac{\mathrm{mK}^2}{\mathrm{~L}}\)
  3. C \(\frac{\mathrm{K}^2}{\mathrm{~mL}}\)
  4. D \(\mathrm{mK}^2 \mathrm{~L}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{\mathrm{L}}{\mathrm{mK}^2}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \mathrm{I}=\mathrm{mK}^2 \text { and } \mathrm{L}=\mathrm{I} \omega=\mathrm{mK}^2 \omega \\ & \therefore \omega=\frac{\mathrm{L}}{\mathrm{mK}^2}\end{aligned}\)