MHT CET · Physics · Work Power Energy
A body of mass 1 kg begins to move under the action of a time dependent force \(\vec{F}=\left(t \hat{i}+2 t^2 \hat{j}\right) N\), where \(\hat{i}\) and \(\hat{j}\) are unit vectors along \(x\) and \(y\) axis. The power developed by above force at time \(t=3\) second will be
- A \(337 \cdot 5 \mathrm{~W}\)
- B \(228 \cdot 5 \mathrm{~W}\)
- C \(422 \cdot 5 \mathrm{~W}\)
- D \(126 \cdot 5 \mathrm{~W}\)
Answer & Solution
Correct Answer
(A) \(337 \cdot 5 \mathrm{~W}\)
Step-by-step Solution
Detailed explanation
\(\vec{a}(t) = \vec{F}(t)/m = \left(t \hat{i}+2 t^2 \hat{j}\right) \mathrm{m/s^2}\) \(\vec{v}(t) = \int \vec{a}(t) dt = \left(\frac{t^2}{2} \hat{i}+\frac{2 t^3}{3} \hat{j}\right) \mathrm{m/s}\)
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