MHT CET · Physics · Rotational Motion
A body is rotating about its own axis. Its rotational kinetic energy is ' \(x\) ' and its angular momentum is ' y '. Hence its moment of inertia about its own axis is
- A \(\frac{x^2}{2 y}\)
- B \(\frac{y^2}{2 x}\)
- C \(\frac{x}{2 y}\)
- D \(\frac{y}{2 x}\)
Answer & Solution
Correct Answer
(B) \(\frac{y^2}{2 x}\)
Step-by-step Solution
Detailed explanation
\( KE_{rot} = \frac{1}{2} I \omega^2 \) and \( L = I \omega \) \( \omega = \frac{L}{I} \)
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