MHT CET · Physics · Oscillations
A body is performing S.H.M. of amplitude 'A'. The displacement of the body from a point where kinetic energy is maximum to a point where potential energy is maximum, is
- A zero
- B \(\pm \mathrm{A}\)
- C \(\pm \frac{\mathrm{A}}{2}\)
- D \(\pm \frac{\mathrm{A}}{4}\)
Answer & Solution
Correct Answer
(B) \(\pm \mathrm{A}\)
Step-by-step Solution
Detailed explanation
Kinetic energy is maximum at the mean position and potential energy is maximum at the extreme positions on either side, The distance between mean and extreme position is A.
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