MHT CET · Physics · Thermal Properties of Matter
A body cools from \(80^{\circ} \mathrm{C}\) to \(50^{\circ} \mathrm{C}\) in 5 min . In the next time of ' \(t\) ' min, the body continues to cool from \(50^{\circ} \mathrm{C}\) to \(30^{\circ} \mathrm{C}\). The total time taken by the body to cool from \(80^{\circ} \mathrm{C}\) to \(30^{\circ} \mathrm{C}\) is
[The temperature of the surroundings is \(20^{\circ} \mathrm{C}\).]
- A 7.5 min
- B 10 min
- C 12.5 min
- D 15.0 min
Answer & Solution
Correct Answer
(C) 12.5 min
Step-by-step Solution
Detailed explanation
\(\frac{80 - 50}{5} = K \left( \frac{80 + 50}{2} - 20 \right)\) \(6 = K(45)\)
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