MHT CET · Physics · Center of Mass Momentum and Collision
A block of mass 'm' moving along a straight line with constant velocity \(3 \overrightarrow{\mathrm{V}}\) collides
with another block of same mass at rest. They stick together and move with
common velocity. The common velocity is
- A \(\frac{3 \vec{v}}{2}\)
- B \(2 \vec{V}\)
- C \(\overrightarrow{3} \vec{V}\)
- D \(\vec{V}\)
Answer & Solution
Correct Answer
(A) \(\frac{3 \vec{v}}{2}\)
Step-by-step Solution
Detailed explanation
A block of mass \('m'\) moving along a straight line with constant velocity \(3 \vec{v}\) collides with another block of same mass at rest. They stick together and move with common velocity. The common velocity is \(\frac{3 \vec{v}}{2}\).
\((m+m) v_{2}=m \times 3 v\)
\(v_{2}=\frac{3}{2} \vec{v}\)
\((m+m) v_{2}=m \times 3 v\)
\(v_{2}=\frac{3}{2} \vec{v}\)
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