MHT CET · Physics · Laws of Motion
A block of mass \(4 \mathrm{~kg}\) is placed on a horizontal surface having coefficients of static and kinetic friction as \(0 \cdot 5\) and \(0 \cdot 4\) respectively. If a force, parallel to horizontal surface of \(4 \mathrm{~N}\) is applied to the body, then the force of friction acting on the body will be \(\left[\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right]\)
- A \(16 \mathrm{~N}\)
- B \(20 \mathrm{~N}\)
- C \(8 \mathrm{~N}\)
- D \(4 \mathrm{~N}\)
Answer & Solution
Correct Answer
(D) \(4 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
\(N = mg = 4 \times 10 = 40 \mathrm{~N}\) \(f_{s,max} = \mu_s N = 0.5 \times 40 = 20 \mathrm{~N}\)
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