MHT CET · Physics · Thermal Properties of Matter
A black body has maximum wavelength ' \(\lambda_{\mathrm{m}}\) ' at temperature 2000 K . Its maximum wavelength at 3000 K will be
- A \(\frac{3}{2} \lambda_{\mathrm{m}}\)
- B \(\frac{16}{81} \lambda_{\mathrm{m}}\)
- C \(\frac{81}{16} \lambda_m\)
- D \(\frac{2}{3} \lambda_{\mathrm{m}}\)
Answer & Solution
Correct Answer
(D) \(\frac{2}{3} \lambda_{\mathrm{m}}\)
Step-by-step Solution
Detailed explanation
\( \lambda_{\mathrm{m}1} T_1 = \lambda_{\mathrm{m}2} T_2 \) \( \lambda_{\mathrm{m}} \times 2000 \text{ K} = \lambda_{\mathrm{m}2} \times 3000 \text{ K} \)
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