MHT CET · Physics · Wave Optics
A beam of light having wavelength \(5400 Å\) from a distance source falls on a single slit \(0.96 \mathrm{~mm}\) wide and the resultant diffraction pattern is observed on a screen \(2 \mathrm{~m}\) away. What is the distance between the first dark fringe on either side of central bright fringe?
- A 4.8 mm
- B 1.2 mm
- C 2.4 mm
- D 3.6 mm
Answer & Solution
Correct Answer
(C) 2.4 mm
Step-by-step Solution
Detailed explanation
\(
\lambda=5.4 \times 10^{-7} \mathrm{~m}, \mathrm{D}=2 \mathrm{~m} \text { and } \mathrm{a}=0.96\) \(\times 10^{-3} \mathrm{~m}
\)
Distance between the dark fringes on either side of the central bright fringe \(=\frac{2 \lambda \mathrm{D}}{\mathrm{a}}=2.4 \mathrm{~mm}\)
\lambda=5.4 \times 10^{-7} \mathrm{~m}, \mathrm{D}=2 \mathrm{~m} \text { and } \mathrm{a}=0.96\) \(\times 10^{-3} \mathrm{~m}
\)
Distance between the dark fringes on either side of the central bright fringe \(=\frac{2 \lambda \mathrm{D}}{\mathrm{a}}=2.4 \mathrm{~mm}\)
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