MHT CET · Physics · Magnetic Effects of Current
A beam of electrons at rest is accelerated by a potential \(V\). This beam experiences a force \(F\) in a uniform magnetic field. The accelerating field is increased to \(V\) ' and the force experienced by the electrons in the same field is ' \(2 F\) ' . The ratio is \(\frac{V}{V^{\prime}}\)
- A \(2: 1\)
- B \(1: 2\)
- C \(1: 4\)
- D \(1: 1\)
Answer & Solution
Correct Answer
(C) \(1: 4\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { K.E. } \frac{1}{2} m v^2=e V \\ & \therefore v=\sqrt{\frac{2 e V}{m}} \\ & F=e V B=e \sqrt{\frac{2 e V}{m}} B \\ & \text { Given } F^{\prime}=2 F=2 e \sqrt{\frac{2 e V}{m}} B \\ & \Rightarrow \frac{1}{2} e \sqrt{\frac{2 e V^{\prime}}{m}} B=e \sqrt{\frac{2 e V}{m}} B \\ & \Rightarrow V^{\prime}=4 V\end{aligned}\)
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