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MHT CET · Physics · Magnetic Effects of Current

A bar magnet of magnetic moment \(5 \mathrm{Am}^{2}\) is placed in a uniform magnetic induction \(3 \times 10^{-5} \mathrm{~T}\). If each pole of a magnet experiences a force of \(2 \cdot 5 \times 10^{-4} \mathrm{~N}\) then the magnetic length of the magnet is

  1. A \(0.8 \mathrm{~m}\)
  2. B \(0 \cdot 2 \mathrm{~m}\)
  3. C \(0.6 \mathrm{~m}\)
  4. D \(0 \cdot 4 \mathrm{~m}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(0.6 \mathrm{~m}\)

Step-by-step Solution

Detailed explanation

\(\mathrm{F}=\mathrm{mB} \quad\) where \(\mathrm{m}\) is pole strength.
\(
\therefore \mathrm{m}=\frac{\mathrm{F}}{\mathrm{B}}=\frac{2.5 \times 10^{-4}}{3 \times 10^{-5}}=\frac{25}{3} \mathrm{Am}
\)
Magnetic moment \(\mathrm{M}=\mathrm{mL}\)
\(
\therefore \mathrm{L}=\frac{\mathrm{M}}{\mathrm{m}}=\frac{5 \times 3}{25}=0.6 \mathrm{~m}
\)