MHT CET · Physics · Alternating Current
A 42 mH inductor is connected to \(200 \mathrm{~V}, 50 \mathrm{~Hz}\) a.c. supply. The r.m.s. value of current in the circuit will be nearly [ Take \(\pi=\frac{22}{7}\) ]
- A \(15.15 \mathrm{~A}\)
- B \(9.15 \mathrm{~A}\)
- C 8.15 A
- D 6.15 A
Answer & Solution
Correct Answer
(A) \(15.15 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \mathrm{X}_{\mathrm{L}} & =\omega \mathrm{L} \\ & =2 \pi \mathrm{~F} . \mathrm{L} \\ & =2 \times \pi \times 50 \times 42 \times 10^{-3} \\ & =13.194 \Omega \\ \mathrm{I}_{\mathrm{RMS}} & =\frac{\mathrm{V}}{\mathrm{X}_{\mathrm{L}}}=\frac{200}{13.194}=15.15 \mathrm{~A}\end{aligned}\)
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