MHT CET · Physics · Current Electricity
A \(2 \mathrm{~V}\) battery, a \(990 \Omega\) resistor and \(\mathrm{a}\) potentiometer of \(2 \mathrm{~m}\) length, all are connected in series of the resistance of potentiometer wire is \(10 \Omega\), then the potential gradient of the potentiometer wire is
- A \(0.05 \mathrm{Vm}^{-1}\)
- B \(0.5 \mathrm{Vm}^{-1}\)
- C \(0.01 \mathrm{Vm}^{-1}\)
- D \(0.1 \mathrm{Vm}^{-1}\)
Answer & Solution
Correct Answer
(C) \(0.01 \mathrm{Vm}^{-1}\)
Step-by-step Solution
Detailed explanation
Potential gradient \(x=\frac{e}{\left(R+R_{h}+r\right)} \cdot \frac{R}{L}\)
\(
\Rightarrow x=\frac{2}{(990+10)} \times \frac{10}{2}=0.01 \mathrm{Vm}^{-1}
\)
\(
\Rightarrow x=\frac{2}{(990+10)} \times \frac{10}{2}=0.01 \mathrm{Vm}^{-1}
\)
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