MHT CET · Physics · Electrostatics
90 J of work is done to move an electric charge of magnitude 3 C from a place A , where potential is -10 V to another place B , where potential is ' \(\mathrm{V}_1\) ' volt. The value of \(\mathrm{V}_1\) is
- A 10 V
- B 20 V
- C 30 V
- D -40 V
Answer & Solution
Correct Answer
(B) 20 V
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
& \mathrm{W}=\mathrm{q} \Delta \mathrm{~V} \\
& \mathrm{~W}=\mathrm{q}\left(\mathrm{~V}_1-\mathrm{V}_{\mathrm{A}}\right) \\
& \mathrm{W}=3\left[\mathrm{~V}_1-(-10)\right] \\
& \frac{90}{3}=\mathrm{V}_1+10 \\
& \mathrm{~V}_1=20 \mathrm{~V}
\end{aligned}\)
& \mathrm{W}=\mathrm{q} \Delta \mathrm{~V} \\
& \mathrm{~W}=\mathrm{q}\left(\mathrm{~V}_1-\mathrm{V}_{\mathrm{A}}\right) \\
& \mathrm{W}=3\left[\mathrm{~V}_1-(-10)\right] \\
& \frac{90}{3}=\mathrm{V}_1+10 \\
& \mathrm{~V}_1=20 \mathrm{~V}
\end{aligned}\)
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