MHT CET · Physics · Nuclear Physics
\({ }_{88} \mathrm{R}_{\mathrm{a}}^{226}\) is converted into \({ }_{82} \mathrm{P}_{\mathrm{b}}^{206}\) by emission of alpha \((\alpha)\) and beta \((\beta)\) particles. The number of alpha and beta particles emitted are respectively
- A 5,4
- B 4,5
- C 6,4
- D 4,6
Answer & Solution
Correct Answer
(A) 5,4
Step-by-step Solution
Detailed explanation
Balance mass number (A): \(226 = 206 + 4x + 0y\) \(4x = 226 - 206 = 20\)
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