MHT CET · Physics · Kinetic Theory of Gases
500 gram of a diatomic gas is enclosed at a pressure of \(10^5 \mathrm{Nm}^{-2}\). The density of the gas is \(5 \mathrm{kgm}^{-3}\). The energy of one mole of the gas due to its thermal motion is [consider the gas molecule as a rigid rotator]
- A \(1.5 \times 10^4 \mathrm{~J}\)
- B \(2.5 \times 10^4 \mathrm{~J}\)
- C \(1.5 \times 10^7 \mathrm{~J}\)
- D \(2.5 \times 10^7 \mathrm{~J}\)
Answer & Solution
Correct Answer
(B) \(2.5 \times 10^4 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\(f = 5\) \(V = m/\rho = 0.5 \mathrm{kg} / 5 \mathrm{kgm}^{-3} = 0.1 \mathrm{m}^3\)
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