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MHT CET · Physics · Thermal Properties of Matter

\(22 \mathrm{~g}\) of carbon dioxide at \(27^{\circ} \mathrm{C}\) is mixed in closed container with \(16 \mathrm{~g}\) of oxygen at \(37^{\circ} \mathrm{C}\). If both gases are considered as ideal gases, then the temperature of the mixture is nearly

  1. A \(22.2^{\circ} \mathrm{C}\)
  2. B \(33.5^{\circ} \mathrm{C}\)
  3. C \(31.5^{\circ} \mathrm{C}\)
  4. D \(28.5^{\circ} \mathrm{C}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(31.5^{\circ} \mathrm{C}\)

Step-by-step Solution

Detailed explanation

Let \(T^{\circ} \mathrm{C}\) be the temperature of the mixture.
heat given by \(\mathrm{O}_2=\) heat absorbed by \(\mathrm{CO}_2\)
\(\begin{aligned} & \Rightarrow \mu_1 C_{V_1} \Delta T=\mu_2 C_{V_2} \Delta T \\ & \Rightarrow \frac{22}{44}(3 R)(T-27)=\frac{16}{32}\left(\frac{5}{2} R\right)(37-T) \\ & \Rightarrow 3(T-27)=\frac{5}{2}(37-T) \\ & \Rightarrow 6 T-162=185-5 T \\ & \Rightarrow 11 T=347 \\ & \Rightarrow T=31.5 \circ \mathrm{C}\end{aligned}\)
From MHT CET
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