1000 small water drops of equal size combine to form a big drop. The ratio of final surface energy to the total initial surface energy is

Radii of the bigger and smaller drops are related as, \(\mathrm{R} \propto \mathrm{n}^{\frac{1}{3}} \mathrm{r}\)
Now, surface energy \(E=T d A=T \times 4 \pi R^2\)
\(\therefore \frac{\mathrm{E}_2}{\mathrm{E}_1}=\frac{4 \pi \mathrm{R}^2 \times \mathrm{T}}{\mathrm{n} \times 4 \pi \mathrm{r}^2 \mathrm{~T}} \)
\( \therefore \frac{\mathrm{E}_2}{\mathrm{E}_1} =\frac{\mathrm{R}^2}{\mathrm{nr}^2}=\frac{\mathrm{n}^{\frac{2}{3}} \times \mathrm{r}^2}{\mathrm{nr}^2} \)
\( \frac{\mathrm{E}_2}{\mathrm{E}_1}=\frac{1}{\mathrm{n}^{\frac{1}{3}}}=\frac{1}{1000^{\frac{1}{3}}} \)
\( \therefore \frac{\mathrm{E}_2}{\mathrm{E}_1} =1: 10\)