MHT CET · Maths · Differential Equations
\(\mathrm{y}=\mathrm{e}^x(\mathrm{~A} \cos x+\mathrm{B} \sin x)\) is the solution of the differential equation
- A \(x^2 \frac{\mathrm{~d}^2 \mathrm{y}}{\mathrm{d} x^2}+\left(1+\mathrm{y}^2\right)=0\)
- B \(\frac{\mathrm{d}^2 \mathrm{y}}{\mathrm{d} x^2}-\frac{\mathrm{dy}}{\mathrm{d} x}+\mathrm{y}=0\)
- C \(\frac{\mathrm{d}^2 \mathrm{y}}{\mathrm{d} x^2}-2 \frac{\mathrm{dy}}{\mathrm{d} x}+2 \mathrm{y}=0\)
- D \(x \frac{\mathrm{~d}^2 \mathrm{y}}{\mathrm{d} x^2}-2 \frac{\mathrm{dy}}{\mathrm{d} x}+2 \mathrm{y}=0\)
Answer & Solution
Correct Answer
(C) \(\frac{\mathrm{d}^2 \mathrm{y}}{\mathrm{d} x^2}-2 \frac{\mathrm{dy}}{\mathrm{d} x}+2 \mathrm{y}=0\)
Step-by-step Solution
Detailed explanation
Given solution: \(\mathrm{y}=\mathrm{e}^x(\mathrm{~A} \cos x+\mathrm{B} \sin x)\) This implies roots of characteristic equation are \(r = \alpha \pm i\beta = 1 \pm i\).
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