MHT CET · Maths · Indefinite Integration
\(\int[\sin (\log x)+\cos (\log x)] d x\) is equal to
- A \(x \cos (\log x)+c\)
- B \(\cos (\log x)+c\)
- C \(x \sin (\log x)+c\)
- D \(\sin (\log x)+c\)
Answer & Solution
Correct Answer
(C) \(x \sin (\log x)+c\)
Step-by-step Solution
Detailed explanation
\(\int[\sin (\log x)+\cos (\log x)] d x \)
\( =\int \frac{d}{d x}\{x \sin (\log x)\} d x \)
\( =x \sin (\log x)+c\)
\( =\int \frac{d}{d x}\{x \sin (\log x)\} d x \)
\( =x \sin (\log x)+c\)
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