MHT CET · Maths · Indefinite Integration
\(\int x \log x d x\) is equal to
- A \(\frac{x^{2}}{4}(2 \log x-1)+c\)
- B \(\frac{x^{2}}{2}(2 \log x-1)+c\)
- C \(\frac{x^{2}}{4}(2 \log x+1)+c\)
- D \(\frac{x^{2}}{2}(2 \log x+1)\)
Answer & Solution
Correct Answer
(A) \(\frac{x^{2}}{4}(2 \log x-1)+c\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \int \frac{x}{\Pi} \log _{I} x d x &=\log x \cdot \frac{x^{2}}{2}-\int \frac{1}{x} \cdot \frac{x^{2}}{2} d x \\ &=\frac{x^{2}}{2} \log x-\frac{1}{2} \frac{x^{2}}{2}+c \\ &=\frac{x^{2}}{4}(2 \log x-1)+c \end{aligned}\)
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