MHT CET · Maths · Indefinite Integration
\(\int \frac{x+\sin x}{1+\cos x} \mathrm{~d} x=\)
- A \(x \cos x+c\), where \(c\) is the constant integration
- B \(x \tan x+c\), where \(c\) is the constant integration
- C \(x \tan \frac{x}{2}+c\), where \(c\) is the constant integration
- D \(x \sec ^2 \frac{x}{2}+c\), where \(c\) is the constant integration
Answer & Solution
Correct Answer
(C) \(x \tan \frac{x}{2}+c\), where \(c\) is the constant integration
Step-by-step Solution
Detailed explanation
\( \int \frac{x+\sin x}{1+\cos x} \mathrm{~d} x = \int \frac{x+2\sin\frac{x}{2}\cos\frac{x}{2}}{2\cos^2\frac{x}{2}} \mathrm{~d} x \) \( = \int \left( \frac{x}{2\cos^2\frac{x}{2}} + \frac{2\sin\frac{x}{2}\cos\frac{x}{2}}{2\cos^2\frac{x}{2}} \right) \mathrm{~d} x \)
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