MHT CET · Maths · Limits
\(\lim _{x \rightarrow \infty} \frac{\mathrm{e}^{x^4}-1}{\mathrm{e}^{x^4}+1}=\)
- A \(1\)
- B e
- C \(\frac{1}{\mathrm{e}}\)
- D not defined
Answer & Solution
Correct Answer
(A) \(1\)
Step-by-step Solution
Detailed explanation
\( \lim _{x \rightarrow \infty} \frac{\mathrm{e}^{x^4}-1}{\mathrm{e}^{x^4}+1} = \lim _{x \rightarrow \infty} \frac{1-\mathrm{e}^{-x^4}}{1+\mathrm{e}^{-x^4}} \) \( = \frac{1-0}{1+0} \)
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