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MHT CET · Maths · Limits

\(\lim _{x \rightarrow \infty} \frac{\mathrm{e}^{x^4}-1}{\mathrm{e}^{x^4}+1}=\)

  1. A \(1\)
  2. B e
  3. C \(\frac{1}{\mathrm{e}}\)
  4. D not defined
Verified Solution

Answer & Solution

Correct Answer

(A) \(1\)

Step-by-step Solution

Detailed explanation

\( \lim _{x \rightarrow \infty} \frac{\mathrm{e}^{x^4}-1}{\mathrm{e}^{x^4}+1} = \lim _{x \rightarrow \infty} \frac{1-\mathrm{e}^{-x^4}}{1+\mathrm{e}^{-x^4}} \) \( = \frac{1-0}{1+0} \)