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MHT CET · Maths · Indefinite Integration

\(\int \frac{\sin x}{\sqrt{5 \sin ^2 x+6 \cos ^2 x}} \mathrm{~d} x=\)

  1. A \(\log \left(\cos x+\sqrt{\cos ^2 x+5}\right)+c \quad, \quad\) where \(c\) is the constant of integration
  2. B \(\log \left(\sin x+\sqrt{6 \cos ^2 x+5}\right)+c, \quad\) where \(c\) is the constant of integration
  3. C \(-\log \left(\cos x+\sqrt{\cos ^2 x+6}\right)+c, \quad\) where \(c\) is the constant of integration
  4. D \(-\log \left(\cos x+\sqrt{\cos ^2 x+5}\right)+c\), where \(c\) is the constant of integration
Verified Solution

Answer & Solution

Correct Answer

(D) \(-\log \left(\cos x+\sqrt{\cos ^2 x+5}\right)+c\), where \(c\) is the constant of integration

Step-by-step Solution

Detailed explanation

\( \int \frac{\sin x}{\sqrt{5 \sin ^2 x+6 \cos ^2 x}} \mathrm{~d} x = \int \frac{\sin x}{\sqrt{5(1-\cos^2 x)+6 \cos^2 x}} \mathrm{~d} x \) \( = \int \frac{\sin x}{\sqrt{5-\cos^2 x+6 \cos^2 x}} \mathrm{~d} x = \int \frac{\sin x}{\sqrt{5+\cos^2 x}} \mathrm{~d} x \)