MHT CET · Maths · Indefinite Integration
\(\int \frac{\sin x}{\sqrt{5 \sin ^2 x+6 \cos ^2 x}} \mathrm{~d} x=\)
- A \(\log \left(\cos x+\sqrt{\cos ^2 x+5}\right)+c \quad, \quad\) where \(c\) is the constant of integration
- B \(\log \left(\sin x+\sqrt{6 \cos ^2 x+5}\right)+c, \quad\) where \(c\) is the constant of integration
- C \(-\log \left(\cos x+\sqrt{\cos ^2 x+6}\right)+c, \quad\) where \(c\) is the constant of integration
- D \(-\log \left(\cos x+\sqrt{\cos ^2 x+5}\right)+c\), where \(c\) is the constant of integration
Answer & Solution
Correct Answer
(D) \(-\log \left(\cos x+\sqrt{\cos ^2 x+5}\right)+c\), where \(c\) is the constant of integration
Step-by-step Solution
Detailed explanation
\( \int \frac{\sin x}{\sqrt{5 \sin ^2 x+6 \cos ^2 x}} \mathrm{~d} x = \int \frac{\sin x}{\sqrt{5(1-\cos^2 x)+6 \cos^2 x}} \mathrm{~d} x \) \( = \int \frac{\sin x}{\sqrt{5-\cos^2 x+6 \cos^2 x}} \mathrm{~d} x = \int \frac{\sin x}{\sqrt{5+\cos^2 x}} \mathrm{~d} x \)
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