MHT CET · Maths · Limits
\(\lim _{x \rightarrow 2}\left(\frac{5 x-8}{8-3 x}\right)^{\frac{3}{2 x-4}}=\)
- A \(e^{5 / 2}\)
- B \(\mathrm{e}^{3 / 2}\)
- C \(\mathrm{e}^2\)
- D \(\mathrm{e}^6\)
Answer & Solution
Correct Answer
(D) \(\mathrm{e}^6\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \lim _{x \rightarrow 2}\left(\frac{5 x-8}{8-3 x}\right) \frac{3}{2 x-4}=e^{\lim _{x \rightarrow 2}\left(\frac{5 x-8}{8-3 x}-1\right) \times \frac{3}{2 x-4}} \\ & =e^{\lim _{x \rightarrow 2} \frac{8(x-2) \times 3}{(8-3 x) 2(x-2)}}=e^6 \\ & \end{aligned}\)
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