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MHT CET · Maths · Indefinite Integration

\(\int \frac{x}{1+x^4} \mathrm{~d} x=\)

  1. A \(\frac{1}{2} \tan ^{-1} x^2+c\), where \(c\) is the constant of integration
  2. B \(2 \tan ^{-1} x+c\), where \(c\) is the constant of integration
  3. C \(\frac{1}{2} \tan ^{-1} x+c, \quad\) where \(c\) is the constant of integration
  4. D \(\tan ^{-1} x^2+c, \quad\) where \(c\) is the constant of integration
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Answer & Solution

Correct Answer

(A) \(\frac{1}{2} \tan ^{-1} x^2+c\), where \(c\) is the constant of integration

Step-by-step Solution

Detailed explanation

Let \(u=x^2 \Rightarrow \mathrm{d}u = 2x \, \mathrm{d}x\) \(\int \frac{x}{1+x^4} \, \mathrm{d}x = \frac{1}{2} \int \frac{1}{1+u^2} \, \mathrm{d}u\)
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