MHT CET · Maths · Indefinite Integration
\(\int \frac{x+1}{x^{2}+5 x+6} d x=\)
- A \(-\log |x+2|-2 \log |x+3|+C\)
- B \(-\log |x+2|+2 \log |x+3|+C\)
- C \(2 \log |x+2|-2 \log |x+3|+C\)
- D \(\log |x+2|+2 \log |x+3|+C\)
Answer & Solution
Correct Answer
(B) \(-\log |x+2|+2 \log |x+3|+C\)
Step-by-step Solution
Detailed explanation
\(I=\int \frac{x+1}{x^{2}+5 x+6} d x\)
Let \(\quad \frac{x+1}{(x+3)(x+2)}=\int\left[\frac{x+1}{(x+3)(x+2)}\right] d x\)
\(\therefore x+1=A(x+2)+B(x+3)\)
When \(x=-2\), we get \(B=-1\)
When \(x=-3\), we get \(A=2\)
\(\therefore I=\int\left[\frac{2}{x+3}-\frac{B}{x+2}\right] d x\)
\(\therefore 2 \log |(x+3)|-\log |x+2|+c\)
Let \(\quad \frac{x+1}{(x+3)(x+2)}=\int\left[\frac{x+1}{(x+3)(x+2)}\right] d x\)
\(\therefore x+1=A(x+2)+B(x+3)\)
When \(x=-2\), we get \(B=-1\)
When \(x=-3\), we get \(A=2\)
\(\therefore I=\int\left[\frac{2}{x+3}-\frac{B}{x+2}\right] d x\)
\(\therefore 2 \log |(x+3)|-\log |x+2|+c\)
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