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MHT CET · Maths · Limits

\(\lim _{x \rightarrow 0} \frac{x \cot 4 x}{\sin ^2 x \cdot \cot ^2(2 x)}\) is equal to

  1. A \(0\)
  2. B \(1\)
  3. C \(4\)
  4. D \(\frac{1}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} \lim _{x \rightarrow 0} \frac{x \cot 4 x}{\sin ^2 x \cot ^2(2 x)} & =\lim _{x \rightarrow 0} \frac{x \tan ^2 2 x}{\sin ^2 x \tan 4 x} \\ & =\lim _{x \rightarrow 0} \frac{4\left(\frac{\tan 2 x}{2 x}\right)^2}{4\left(\frac{\sin x}{x}\right)^2\left(\frac{\tan 4 x}{4 x}\right)} \\ & =1\end{aligned}\)