MHT CET · Maths · Limits
\(\lim _{x \rightarrow 0} \frac{\cos a x-\cos b x}{x^{2}}\) is equal to
- A \(\frac{a^{2}-b^{2}}{2}\)
- B \(\frac{b^{2}-a^{2}}{2}\)
- C \(a^{2}-b^{2}\)
- D \(b^{2}-a^{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{b^{2}-a^{2}}{2}\)
Step-by-step Solution
Detailed explanation
\(\lim _{x \rightarrow 0} \frac{\cos a x-\cos b x}{x^{2}}\)
\(=\lim _{x \rightarrow 0} \frac{-a \sin a x+b \sin b x}{2 x}\) (using L'Hospital's rule)
\(=\lim _{x \rightarrow 0} \frac{-a^{2} \cos a x+b^{2} \sin b x}{2}\)
\(=\frac{b^{2}-a^{2}}{2}\) (using L'Hospital's rule)
\(=\lim _{x \rightarrow 0} \frac{-a \sin a x+b \sin b x}{2 x}\) (using L'Hospital's rule)
\(=\lim _{x \rightarrow 0} \frac{-a^{2} \cos a x+b^{2} \sin b x}{2}\)
\(=\frac{b^{2}-a^{2}}{2}\) (using L'Hospital's rule)
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