MHT CET · Maths · Limits
\(\lim _{x \rightarrow 0} \frac{9^x-4^x}{x\left(9^x+4^x\right)}=\)
- A \(\log \left(\frac{3}{2}\right)\)
- B \(\frac{1}{2} \log \left(\frac{3}{2}\right)\)
- C \(2 \log \left(\frac{3}{2}\right)\)
- D \(2 \log \left(\frac{9}{4}\right)\)
Answer & Solution
Correct Answer
(A) \(\log \left(\frac{3}{2}\right)\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \lim _{x \rightarrow 0} \frac{9^x-4^x}{x\left(9^x+4^x\right)} \\ & =\lim _{x \rightarrow 0} \frac{\left(9^x-1\right)-\left(4^x-1\right)}{x} \times \frac{1}{\left(9^x+4^x\right)} \\ & =\left[\lim _{x \rightarrow 0} \frac{9^x-1}{x}-\lim _{x \rightarrow 0} \frac{4^x-1}{x}\right] \times \lim _{x \rightarrow 0} \frac{1}{\left(9^x \cdot+4^x\right)} \\ & =\log \left(\frac{9}{4}\right) \times \frac{1}{(1+1)} \\ & =\log \left(\frac{3}{2}\right)\end{aligned}\)
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