MHT CET · Maths · Limits
\(\lim _{x \rightarrow 0} \frac{\left(7^x-1\right)^4}{\tan \left(\frac{x}{\mathrm{k}}\right) \cdot \log \left(1+\frac{x^2}{3}\right) \cdot \sin 4 x}=3(\log 7)^3\)
- A \(4(\log 7)^{-1}\)
- B \(\frac{1}{4}(\log 7)^{-1}\)
- C \(4 \log \left(\frac{1}{7}\right)\)
- D \(\frac{1}{4} \log 7\)
Answer & Solution
Correct Answer
(A) \(4(\log 7)^{-1}\)
Step-by-step Solution
Detailed explanation
\(\lim _{x \rightarrow 0} \frac{\left(7^x-1\right)^4}{\tan \left(\frac{x}{\mathrm{k}}\right) \cdot \log \left(1+\frac{x^2}{3}\right) \cdot \sin 4 x} = \lim _{x \rightarrow 0} \frac{\left(x \log 7\right)^4}{\left(\frac{x}{\mathrm{k}}\right) \cdot \left(\frac{x^2}{3}\right) \cdot (4x)}\) \(= \lim _{x \rightarrow 0} \frac{x^4 (\log 7)^4}{\frac{4x^4}{3k}}\)
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