MHT CET · Maths · Trigonometric Ratios & Identities
With usual notations in \(\triangle A B C\) if \(a^2+b^2-c^2=a b\), then measure of angle \(C\) is
- A \(\frac{\pi}{4}\)
- B \(\frac{\pi}{6}\)
- C \(\frac{\pi}{2}\)
- D \(\frac{\pi}{3}\)
Answer & Solution
Correct Answer
(D) \(\frac{\pi}{3}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & a^2+b^2-c^2=a b \\ & \Rightarrow \frac{a^2+b^2-c^2}{2 a b}=\frac{1}{2} \\ & \Rightarrow \cos c=\frac{1}{2} \\ & \Rightarrow c=\frac{\pi}{3}\end{aligned}\)
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