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MHT CET · Maths · Properties of Triangles

With usual notations, if the angles \(A, B, C\) of a \(\triangle A B C\) are in A.P. and \(b: c=\sqrt{3}: \sqrt{2}\),
then \(\angle \mathrm{A}=\)

  1. A \(55^{\circ}\)
  2. B \(45^{\circ}\)
  3. C \(35^{\circ}\)
  4. D \(75^{\circ}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(75^{\circ}\)

Step-by-step Solution

Detailed explanation

(B)
Since \(A, B, C\) are in A.P., \(2 B=A+C \Rightarrow B=60^{\circ}\)
We know that, \(\frac{\sin B}{b}=\frac{\sin C}{c} \Rightarrow \sin C=\frac{C}{b} \times \sin 60^{\circ}\)
\(\therefore \sin C=\frac{\sqrt{2}}{\sqrt{3}} \times \frac{\sqrt{3}}{2}=\frac{1}{\sqrt{2}}\)
\(\therefore \quad C=45^{\circ} \Rightarrow A=180^{\circ}-\left(60^{\circ}+45^{\circ}\right)=75^{\circ}\)