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MHT CET · Maths · Properties of Triangles

With usual notations, if in \(\triangle \mathrm{ABC}, 8\) is semi perimeter and \((\mathrm{s}-a)(\mathrm{s}-\mathrm{b})=\mathrm{s}(\mathrm{s}-\mathrm{c})\),
then \(\triangle A B C\) is

  1. A an equilateral triangle
  2. B an obtuse angle triangle
  3. C a right angled triangle
  4. D an acute angle triangle
Verified Solution

Answer & Solution

Correct Answer

(C) a right angled triangle

Step-by-step Solution

Detailed explanation

We have
\(\begin{array}{l}
\sin \frac{C}{2}=\sqrt{\frac{(s-a)(s-b)}{a b}} \Rightarrow \sin ^{2} \frac{C}{2}=\frac{(s-a)(s-b)}{a b} \text { and } \\
\cos \frac{C}{2}=\sqrt{\frac{s(s-c)}{a b}} \Rightarrow \cos ^{2} \frac{C}{2}=\frac{s(s-c)}{a b} \\
\text { Given }(s-a)(s-b)=s(s-c) \\
\therefore \quad a b \sin ^{2} \frac{C}{2}=a b \cos ^{2} \frac{C}{2}
\end{array}\)
\(\therefore \tan ^{2} \frac{C}{2}=1 \Rightarrow \tan \frac{C}{2}=1 \Rightarrow \frac{C}{2}=45^{\circ} \Rightarrow C=90^{\circ}\)
\(\therefore \triangle \mathrm{ABC}\) is a right angled triangle