MHT CET · Maths · Properties of Triangles
With usual notation, in triangle \(\mathrm{ABC}, \mathrm{m} \angle \mathrm{A}=30^{\circ}\), then the value of \(\left(1+\frac{a}{c}+\frac{b}{c}\right)\left(1+\frac{c}{b}-\frac{a}{b}\right)\) is equal to
- A \(\frac{2+\sqrt{3}}{2}\)
- B \(2+\sqrt{3}\)
- C \(\frac{1+\sqrt{3}}{2}\)
- D \(1+\sqrt{3}\)
Answer & Solution
Correct Answer
(B) \(2+\sqrt{3}\)
Step-by-step Solution
Detailed explanation
\( \left(\frac{c+a+b}{c}\right)\left(\frac{b+c-a}{b}\right) \) \( \frac{(b+c)^2 - a^2}{bc} \)
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