MHT CET · Maths · Definite Integration
Which of the following is true?
- A \(\int_{0}^{1} e^{x} d x=e\)
- B \(\int_{0}^{1} 2^{x} d x=\log 2\)
- C \(\int_{0}^{1} \sqrt{x} d x=\frac{2}{3}\)
- D \(\int_{0}^{1} x d x=\frac{1}{3}\)
Answer & Solution
Correct Answer
(C) \(\int_{0}^{1} \sqrt{x} d x=\frac{2}{3}\)
Step-by-step Solution
Detailed explanation
\(\int_{0}^{1} e^{x} d x=\left[e^{x}\right]_{0}^{1}=e-1\)
(b) \(\int_{0}^{1} 2^{x} d x=\left[\frac{2^{x}}{\log _{e} 2}\right]_{0}^{1}=\frac{1}{\log 2} \cdot\left(2-2^{0}\right)=\frac{1}{\log 2}\)
(c) \(\int_{0}^{1} \sqrt{x} d x=\left[\frac{x^{3 / 2}}{3 / 2}\right]_{0}^{1}=\frac{2}{3}\)
(d) \(\int_{0}^{1} x d x=\left[\frac{x^{2}}{2}\right]_{0}^{1}=\frac{1}{2}\)
(b) \(\int_{0}^{1} 2^{x} d x=\left[\frac{2^{x}}{\log _{e} 2}\right]_{0}^{1}=\frac{1}{\log 2} \cdot\left(2-2^{0}\right)=\frac{1}{\log 2}\)
(c) \(\int_{0}^{1} \sqrt{x} d x=\left[\frac{x^{3 / 2}}{3 / 2}\right]_{0}^{1}=\frac{2}{3}\)
(d) \(\int_{0}^{1} x d x=\left[\frac{x^{2}}{2}\right]_{0}^{1}=\frac{1}{2}\)
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