MHT CET · Maths · Mathematical Reasoning
Which of the following is correct statement?
(a) \(S_1:(p \wedge q) \equiv \sim(p \rightarrow \sim q)\).
(b) \(S_2:(p \wedge q) \wedge(\sim p v \sim q)\) is tautology.
(c) \(\left.S_3:[p \wedge(p \rightarrow \sim q)] \rightarrow q\right)\) is contradiction.
(d) \(S_4: p \rightarrow(q \rightarrow p)\) is contingency.
- A Statement \(S_3\) is correct,
- B Statement \(S_1\) is correct,
- C Statement \(S_1\) and \(S_2\) are correct,
- D Statement \(S_4\) is correct,
Answer & Solution
Correct Answer
(B) Statement \(S_1\) is correct,
Step-by-step Solution
Detailed explanation
\(
\begin{aligned}
& \because \sim(p \rightarrow q) \equiv p \wedge \sim q \\
& \Rightarrow \sim(p \rightarrow \sim q) \equiv p \wedge \sim(\sim q) \equiv p \wedge q
\end{aligned}
\)
Hence, \(S_1\) is correct
\begin{aligned}
& \because \sim(p \rightarrow q) \equiv p \wedge \sim q \\
& \Rightarrow \sim(p \rightarrow \sim q) \equiv p \wedge \sim(\sim q) \equiv p \wedge q
\end{aligned}
\)
Hence, \(S_1\) is correct
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