MHT CET · Maths · Circle
Two tangents to the circle \(x^2+y^2=4\) at the points \(A\) and \(B\) meet at \(\mathrm{P}(-4,0)\). Then the area of quadrilateral PAOB , where 'O' is the origin is
- A \(8 \sqrt{3}\) sq. units
- B \(\frac{4}{\sqrt{3}}\) sq. units
- C \(4 \sqrt{3}\) sq. units
- D \(\sqrt{3}\) sq. units
Answer & Solution
Correct Answer
(C) \(4 \sqrt{3}\) sq. units
Step-by-step Solution
Detailed explanation
\(r=OA=2\) \(OP=\sqrt{(-4-0)^2+(0-0)^2}=4\)
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