MHT CET · Maths · Circle
Two tangents to the circle \(x^2+y^2=4\) at the points \(\mathrm{A}\) and \(\mathrm{B}\) meet at the point \(\mathrm{P}(-4,0)\). Then the area of the quadrilateral \(\mathrm{PAOB}, \mathrm{O}\) being the origin, is
- A \(2 \sqrt{3}\) sq. units
- B \(8 \sqrt{3}\) sq. units
- C \(4 \sqrt{3}\) sq. units
- D \(6 \sqrt{3}\) sq. units
Answer & Solution
Correct Answer
(C) \(4 \sqrt{3}\) sq. units
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \text {Required area } & =2 \times \text { Area of } \triangle \mathrm{PBO} \\ & =2 \times \frac{1}{2} \times 2 \times 2 \sqrt{3} \\ & =4 \sqrt{3} \text { sq. units }\end{aligned}\)
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