MHT CET · Maths · Probability
Two dice are rolled one after the other. The probability that the number on the first is smaller than the number on the second, is
- A \(\frac{1}{2}\)
- B \(\frac{7}{18}\)
- C \(\frac{3}{4}\)
- D \(\frac{5}{12}\)
Answer & Solution
Correct Answer
(D) \(\frac{5}{12}\)
Step-by-step Solution
Detailed explanation
Let \(A_{i}=\) Event of getting a number \(i\) on first die.
\(B_{i}=\) Event of getting a number more than \(i\) on
second die.
The required probability
$$
\(B_{i}=\) Event of getting a number more than \(i\) on
second die.
The required probability
$$
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