Two cards are drawn successively with replacement from well shuffled pack of 52 cards, then the probability distribution of number of queens is

Let \(\mathrm{X}\) denote the number of queens.
\(\therefore\) Possible values of \(\mathrm{X}\) are \(0,1,2\).
\(\mathrm{P}(\text { queen })=\frac{4}{52}=\frac{1}{13} \)
\( \mathrm{P}(\text { not a queen }) =\frac{48}{52}=\frac{12}{13} \)
\( \mathrm{P}(\mathrm{X}=0) =\frac{12}{13} \times \frac{12}{13} \)
\( =\frac{144}{169} \)
\( \mathrm{P}(\mathrm{X}=1) =\left(\frac{1}{13} \times \frac{12}{13}\right)+\left(\frac{12}{13} \times \frac{1}{13}\right) \)
\( =\frac{12}{169}+\frac{12}{169}=\frac{24}{169} \)
\( \mathrm{P}(\mathrm{X}=2) =\frac{1}{13} \times \frac{1}{13} \)
\( =\frac{1}{169}\)
\(\begin{array}{|c|c|c|c|}
\hline \mathrm{X}=x & 0 & 1 & 2 \\
\hline \mathrm{P}[\mathrm{X}=x] & \frac{144}{169} & \frac{24}{169} & \frac{1}{169} \\
\hline
\end{array}\)
The probability distribution of \(\mathrm{X}\) is