MHT CET · Maths · Vector Algebra
Two adjacent sides of a parallelogram ABCD are given by \(\overline{\mathrm{AB}}=2 \hat{i}+10 \hat{j}+11 \hat{k}\) and \(\overline{\mathrm{AD}}=-\hat{i}+2 \hat{j}+2 \hat{k}\). The side AD is rotated by an acute angle \(\alpha\) in the plane of parallelogram so that AD becomes \(\mathrm{AD}^{\prime}\). If \(\mathrm{AD}^{\prime}\) makes a right angle with the side AB then \(\cos \alpha=\)
- A \(\frac{\sqrt{17}}{8}\)
- B \(\frac{\sqrt{17}}{9}\)
- C \(\frac{\sqrt{17}}{13}\)
- D \(\frac{\sqrt{17}}{16}\)
Answer & Solution
Correct Answer
(B) \(\frac{\sqrt{17}}{9}\)
Step-by-step Solution
Detailed explanation
\(|\overline{\mathrm{AB}}|^2 = 2^2+10^2+11^2 = 225\) \(|\overline{\mathrm{AD}}|^2 = (-1)^2+2^2+2^2 = 9\)
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