MHT CET · Maths · Pair of Lines
To convert the equation \(2 x^2+4 x y+5 y^2-4 x-22 y+29=0\) to homogeneous form the origin is shifted to the point
- A \((2,3)\)
- B \((-2,3)\)
- C \((-2,-3)\)
- D \((1,2)\)
Answer & Solution
Correct Answer
(B) \((-2,3)\)
Step-by-step Solution
Detailed explanation
Let the shifted origin be \( (h,k) \). Partial derivatives with respect to \(x\) and \(y\):
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- If \(A=\left[\begin{array}{ccc}1 & 2 & 1 \\ -1 & 1 & 3\end{array}\right]\) and \(B=\left[\begin{array}{cc}1 & 2 \\ -3 & 1 \\ 0 & 2\end{array}\right]\), then \((A B)^{-1}\)MHT CET 2021 Easy
- The equation of the curve passing through the origin and satisfying the equation \(\left(1+x^2\right) \frac{\mathrm{dy}}{\mathrm{d} x}+2 x y=4 x^2\), isMHT CET 2025 Medium
- The value of \(\int \frac{\mathrm{d} x}{7+6 x-x^2}\) is equal toMHT CET 2024 Hard
- Two circles centered at \((2,3)\) and \((4,5)\) intersects each other. If their radii are equal, then the equation of the common chord isMHT CET 2021 Medium
- Let \(A=\left[\begin{array}{cc}\cos \theta & -\sin \theta \\ -\sin \theta & -\cos \theta\end{array}\right]\), then the inverse of \(A\)
isMHT CET 2010 Medium - The equation of the tangent to the curve \(y=\sqrt{9-2 x^2}\), at the point where the ordinate and abscissa are equal, isMHT CET 2023 Medium
More PYQs from MHT CET
- In double slit experiment, instead of taking slits of equal widths, one slit is made twice as wide as the other. Then in interference patternMHT CET 2024 Medium
- Identify 'A' in the following reaction
MHT CET 2020 Medium - Which among the following statements is NOT correct about \(\mathrm{SN}^2\) reaction mechanism?MHT CET 2022 Medium
- What is spin only magnetic moment of an element having one unpaired electron?MHT CET 2021 Hard
- If \(\mathrm{AX}=\mathrm{B}\), where \(\mathrm{A}=\left[\begin{array}{ccc}1 & -1 & 1 \\ 2 & -1 & 0 \\ 3 & 3 & -4\end{array}\right], \mathrm{B}=\left[\begin{array}{l}1 \\ 1 \\ 2\end{array}\right]\) and \(\mathrm{X}=\left[\begin{array}{l}x \\ y \\ z\end{array}\right]\), then \(x+y+z=\)MHT CET 2020 Medium
- Which formula is used to calculate edge length in bcc structure?MHT CET 2023 Easy