MHT CET · Maths · Probability
Three numbers are chosen at random from numbers 1 to 20 . The probability that they are consecutive is
- A \(\frac{1}{190}\)
- B \(\frac{1}{120}\)
- C \(\frac{3}{190}\)
- D \(\frac{5}{190}\)
Answer & Solution
Correct Answer
(C) \(\frac{3}{190}\)
Step-by-step Solution
Detailed explanation
Total ways to choose 3 numbers: \( \binom{20}{3} = \frac{20 \cdot 19 \cdot 18}{3 \cdot 2 \cdot 1} = 1140 \) Favorable ways (consecutive): \( (1,2,3), (2,3,4), \dots, (18,19,20) = 18 \)
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