MHT CET · Maths · Probability
Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three persons apply for the same house is
- A \(\frac{1}{9}\)
- B \(\frac{2}{9}\)
- C \(\frac{7}{9}\)
- D \(\frac{8}{9}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{9}\)
Step-by-step Solution
Detailed explanation
Total number of ways \(=3 \times 3 \times 3=27\)
Favourable number of cases \(=3\)
\(\therefore \quad\) Required probability \(=\frac{3}{27}=\frac{1}{9}\)
Favourable number of cases \(=3\)
\(\therefore \quad\) Required probability \(=\frac{3}{27}=\frac{1}{9}\)
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