MHT CET · Maths · Area Under Curves
There are (in square units) of the region bounded by the parabola \(y=x^2+2\) and the lines \(y=x+1, x=0\) and \(x=3\) is
- A \(\frac{15}{4}\)
- B \(\frac{15}{2}\)
- C \(\frac{21}{2}\)
- D \(\frac{17}{4}\)
Answer & Solution
Correct Answer
(B) \(\frac{15}{2}\)
Step-by-step Solution
Detailed explanation

Required area
\(\begin{aligned}
& =\int_0^3\left\{\left(x^2+2\right)-(x+1)\right\} d x \\
& =\left[\frac{x^3}{3}+2 x-\frac{x^2}{2}-x\right]_0^3 \\
& =\left(9+6-\frac{9}{2}-3\right)-0=\frac{15}{2}
\end{aligned}\)
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