MHT CET · Maths · Permutation Combination
There are 11 points in a plane of which 5 points are collinear. Then the total number of distinct quadrilaterals with vertices at these points is
- A 265
- B 330
- C 250
- D 325
Answer & Solution
Correct Answer
(A) 265
Step-by-step Solution
Detailed explanation
Total ways to choose 4 points: \(\binom{11}{4} = \frac{11 \times 10 \times 9 \times 8}{4 \times 3 \times 2 \times 1} = 330\) Ways to choose 4 collinear points: \(\binom{5}{4} = 5\)
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