MHT CET · Maths · Parabola
The Y-intercept of the common tangent to the parabola \(y^2=32 x\) and \(x^2=108 y\) is
- A \(3\)
- B \(-12\)
- C \(-3\)
- D \(2\)
Answer & Solution
Correct Answer
(B) \(-12\)
Step-by-step Solution
Detailed explanation
Tangent to \(y^2=32x\) is \(y=mx+\frac{8}{m}\). Tangent to \(x^2=108y\) is \(y=mx-27m^2\).
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