MHT CET · Maths · Vector Algebra
The volume of the tetrahedron whose coterminus edges are represented by \(\bar{a}=-12 \hat{i}+\mathrm{p} \hat{\mathrm{k}}, \overline{\mathrm{b}}=3 \hat{\mathrm{j}}-\hat{\mathrm{k}}, \overline{\mathrm{c}}=2 \hat{i}+\hat{\mathrm{j}}-15 \hat{\mathrm{k}}\), is 570 cu. units, then \(\mathrm{p}=\)
- A \(7\)
- B \(-12\)
- C \(-482\)
- D \(482\)
Answer & Solution
Correct Answer
(C) \(-482\)
Step-by-step Solution
Detailed explanation
\([\bar{a} \ \bar{b} \ \bar{c}] = \begin{vmatrix} -12 & 0 & p \\ 0 & 3 & -1 \\ 2 & 1 & -15 \end{vmatrix} = -12(3(-15)-1(-1)) + p(0(1)-2(3))\) \(= -12(-45+1) + p(-6) = -12(-44) - 6p = 528 - 6p\)
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