MHT CET · Maths · Area Under Curves
The volume of the solid formed by rotating the area enclosed between the curve \(y^{2}=4 x, x=4\) and \(x=5\) about \(x\) -axis is (in cubic units)
- A \(18 \pi\)
- B \(36 \pi\)
- C \(9 \pi\)
- D \(24 \pi\)
Answer & Solution
Correct Answer
(A) \(18 \pi\)
Step-by-step Solution
Detailed explanation
Volume of the solid \(=\int_{4}^{5} \pi y^{2} d x\)
\(=\pi \int_{4}^{5} 4 x d x\)
\(=4 \pi\left[\frac{x^{2}}{2}\right]_{4}^{5}\)
\(=2 x(25-16)\)
\(=18 \pi\) cu unit
\(=\pi \int_{4}^{5} 4 x d x\)
\(=4 \pi\left[\frac{x^{2}}{2}\right]_{4}^{5}\)
\(=2 x(25-16)\)
\(=18 \pi\) cu unit
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