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MHT CET · Maths · Area Under Curves

The volume of the solid formed by rotating the area enclosed between the curve \(y^{2}=4 x, x=4\) and \(x=5\) about \(x\) -axis is (in cubic units)

  1. A \(18 \pi\)
  2. B \(36 \pi\)
  3. C \(9 \pi\)
  4. D \(24 \pi\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(18 \pi\)

Step-by-step Solution

Detailed explanation

Volume of the solid \(=\int_{4}^{5} \pi y^{2} d x\)
\(=\pi \int_{4}^{5} 4 x d x\)
\(=4 \pi\left[\frac{x^{2}}{2}\right]_{4}^{5}\)
\(=2 x(25-16)\)
\(=18 \pi\) cu unit